Element Conditions: Show If Child Page's Root Parent Page Has Specific Page ID

How To
1

So I created a page template that has a sidebar with a menu. I want the menu to be conditional based on the parent page. I was able to use the Parent Page conditions for the immediate child of a particular parent page, but of course I ran into the issue of pages that are further down the parent/child relationship structure. So Pages that are grandchildren of a Parent Page.

I saw that you can use a php function in the dynamic data for conditions, but every function I have tried in order to check the current page if it is the ancestor of a root parent page doesn’t seem to work. I am very likely not understanding the functions themselves.

How would I make an element conditional based on the root page ancestor or “grandparent”, if that’s even the correct term?

2

I have this issue as well, and had it working in Oxygen builder, but am having trouble getting it to work in Bricks. I have multiple menus that I want to show in a sidebar based on the top-level page ancestor in the same way that you asked about.

My code returns the proper page ancestor ID, but using it in a condition has not worked. If anyone sees this and can point me in the right direction, I would be grateful.

Here’s my condition:
Screenshot 2024-10-23 at 9.30.22 AM

And my code:

<?php 
function sa_get_page_root() {
  global $post;
  if ($post->post_parent)	{
  	$ancestors=get_post_ancestors($post->ID);
  	$root=count($ancestors)-1;
  	$parent = $ancestors[$root];
  } else {
  	$parent = $post->ID;
  }
  return $parent;
}
3

Update: Since Bricks has become more strict about echoing php in templates, I had to add my custom function as per the Code Review section. I added the following to my functions.php, and it works as expected now:

 add_filter( 'bricks/code/echo_function_names', function() {
  return [
    'sa_get_page_root',
  ];
} );
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